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96m^2-24=0
a = 96; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·96·(-24)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*96}=\frac{-96}{192} =-1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*96}=\frac{96}{192} =1/2 $
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